x^2+48x-72=0

Solution for x^2+48x-72=0 equation:

x^2+48x-72=0

a = 1; b = 48; c = -72;
Δ = b2-4ac
Δ = 482-4·1·(-72)
Δ = 2592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2592}=\sqrt{1296*2}=\sqrt{1296}*\sqrt{2}=36\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-36\sqrt{2}}{2*1}=\frac{-48-36\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+36\sqrt{2}}{2*1}=\frac{-48+36\sqrt{2}}{2}
$